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2y=2(y+2)
We move all terms to the left:
2y-(2(y+2))=0
We calculate terms in parentheses: -(2(y+2)), so:We get rid of parentheses
2(y+2)
We multiply parentheses
2y+4
Back to the equation:
-(2y+4)
2y-2y-4=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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