2y=2/5y+3

Solution for 2y=2/5y+3 equation:

2y=2/5y+3

We move all terms to the left:

2y-(2/5y+3)=0


Domain of the equation: 5y+3)!=0

y∈R


We get rid of parentheses

2y-2/5y-3=0

We multiply all the terms by the denominator


2y*5y-3*5y-2=0

Wy multiply elements

10y^2-15y-2=0

a = 10; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·10·(-2)
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{305}}{2*10}=\frac{15-\sqrt{305}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{305}}{2*10}=\frac{15+\sqrt{305}}{20}
$