2y=3(-3+5/3y)+3

Solution for 2y=3(-3+5/3y)+3 equation:

2y=3(-3+5/3y)+3

We move all terms to the left:

2y-(3(-3+5/3y)+3)=0


Domain of the equation: 3y)+3)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

2y-(3(5/3y-3)+3)=0

We multiply all the terms by the denominator


2y*3y-3)+3)-(3(5=0

We add all the numbers together, and all the variables

2y*3y=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$