2y=3(4y-2)

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Solution for 2y=3(4y-2) equation: 



2y=3(4y-2)

We move all terms to the left:

2y-(3(4y-2))=0



We calculate terms in parentheses: -(3(4y-2)), so:

3(4y-2)

We multiply parentheses

12y-6

Back to the equation:

-(12y-6)



We get rid of parentheses

2y-12y+6=0

We add all the numbers together, and all the variables

-10y+6=0

We move all terms containing y to the left, all other terms to the right

-10y=-6

y=-6/-10

y=3/5

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