2y=3(y-9)=-(3y-18)-y

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Solution for 2y=3(y-9)=-(3y-18)-y equation: 



2y=3(y-9)=-(3y-18)-y

We move all terms to the left:

2y-(3(y-9))=0



We calculate terms in parentheses: -(3(y-9)), so:

3(y-9)

We multiply parentheses

3y-27

Back to the equation:

-(3y-27)



We get rid of parentheses

2y-3y+27=0

We add all the numbers together, and all the variables

-1y+27=0

We move all terms containing y to the left, all other terms to the right

-y=-27

y=-27/-1

y=+27

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