2z(20z+141)=135

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Solution for 2z(20z+141)=135 equation:


Simplifying
2z(20z + 141) = 135

Reorder the terms:
2z(141 + 20z) = 135
(141 * 2z + 20z * 2z) = 135
(282z + 40z2) = 135

Solving
282z + 40z2 = 135

Solving for variable 'z'.

Reorder the terms:
-135 + 282z + 40z2 = 135 + -135

Combine like terms: 135 + -135 = 0
-135 + 282z + 40z2 = 0

Factor a trinomial.
(-15 + -2z)(9 + -20z) = 0

Subproblem 1

Set the factor '(-15 + -2z)' equal to zero and attempt to solve: Simplifying -15 + -2z = 0 Solving -15 + -2z = 0 Move all terms containing z to the left, all other terms to the right. Add '15' to each side of the equation. -15 + 15 + -2z = 0 + 15 Combine like terms: -15 + 15 = 0 0 + -2z = 0 + 15 -2z = 0 + 15 Combine like terms: 0 + 15 = 15 -2z = 15 Divide each side by '-2'. z = -7.5 Simplifying z = -7.5

Subproblem 2

Set the factor '(9 + -20z)' equal to zero and attempt to solve: Simplifying 9 + -20z = 0 Solving 9 + -20z = 0 Move all terms containing z to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -20z = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -20z = 0 + -9 -20z = 0 + -9 Combine like terms: 0 + -9 = -9 -20z = -9 Divide each side by '-20'. z = 0.45 Simplifying z = 0.45

Solution

z = {-7.5, 0.45}

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