2z+18=16-4(z+7)

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Solution for 2z+18=16-4(z+7) equation: 



2z+18=16-4(z+7)

We move all terms to the left:

2z+18-(16-4(z+7))=0



We calculate terms in parentheses: -(16-4(z+7)), so:

16-4(z+7)

determiningTheFunctionDomain
-4(z+7)+16

We multiply parentheses

-4z-28+16

We add all the numbers together, and all the variables

-4z-12

Back to the equation:

-(-4z-12)



We get rid of parentheses

2z+4z+12+18=0

We add all the numbers together, and all the variables

6z+30=0

We move all terms containing z to the left, all other terms to the right

6z=-30

z=-30/6

z=-5

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