2z+2(3z+4)=6z-(3-2z)

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Solution for 2z+2(3z+4)=6z-(3-2z) equation: 



2z+2(3z+4)=6z-(3-2z)

We move all terms to the left:

2z+2(3z+4)-(6z-(3-2z))=0

We add all the numbers together, and all the variables

2z+2(3z+4)-(6z-(-2z+3))=0

We multiply parentheses

2z+6z-(6z-(-2z+3))+8=0



We calculate terms in parentheses: -(6z-(-2z+3)), so:

6z-(-2z+3)

We get rid of parentheses

6z+2z-3

We add all the numbers together, and all the variables

8z-3

Back to the equation:

-(8z-3)



We add all the numbers together, and all the variables

8z-(8z-3)+8=0

We get rid of parentheses

8z-8z+3+8=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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