2z+2=(z+1)+(z+1)

Solution for 2z+2=(z+1)+(z+1) equation:

Simplifying
2z + 2 = (z + 1) + (z + 1)

Reorder the terms:
2 + 2z = (z + 1) + (z + 1)

Reorder the terms:
2 + 2z = (1 + z) + (z + 1)

Remove parenthesis around (1 + z)
2 + 2z = 1 + z + (z + 1)

Reorder the terms:
2 + 2z = 1 + z + (1 + z)

Remove parenthesis around (1 + z)
2 + 2z = 1 + z + 1 + z

Reorder the terms:
2 + 2z = 1 + 1 + z + z

Combine like terms: 1 + 1 = 2
2 + 2z = 2 + z + z

Combine like terms: z + z = 2z
2 + 2z = 2 + 2z

Add '-2' to each side of the equation.
2 + -2 + 2z = 2 + -2 + 2z

Combine like terms: 2 + -2 = 0
0 + 2z = 2 + -2 + 2z
2z = 2 + -2 + 2z

Combine like terms: 2 + -2 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.