2z+2z+(3z-2)+(3z-2)=76

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Solution for 2z+2z+(3z-2)+(3z-2)=76 equation: 



2z+2z+(3z-2)+(3z-2)=76

We move all terms to the left:

2z+2z+(3z-2)+(3z-2)-(76)=0

We add all the numbers together, and all the variables

4z+(3z-2)+(3z-2)-76=0

We get rid of parentheses

4z+3z+3z-2-2-76=0

We add all the numbers together, and all the variables

10z-80=0

We move all terms containing z to the left, all other terms to the right

10z=80

z=80/10

z=8

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