2z+2z+2z+4z-8z=12

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Solution for 2z+2z+2z+4z-8z=12 equation: 



2z+2z+2z+4z-8z=12

We move all terms to the left:

2z+2z+2z+4z-8z-(12)=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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