2z+2z-3z+2=20

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Solution for 2z+2z-3z+2=20 equation:



2z+2z-3z+2=20
We move all terms to the left:
2z+2z-3z+2-(20)=0
We add all the numbers together, and all the variables
z-18=0
We move all terms containing z to the left, all other terms to the right
z=18

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