2z+2z-z+4z+3z=20

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Solution for 2z+2z-z+4z+3z=20 equation: 



2z+2z-z+4z+3z=20

We move all terms to the left:

2z+2z-z+4z+3z-(20)=0

We add all the numbers together, and all the variables

10z-20=0

We move all terms containing z to the left, all other terms to the right

10z=20

z=20/10

z=2

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