2z+2z=3z+29

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Solution for 2z+2z=3z+29 equation: 



2z+2z=3z+29

We move all terms to the left:

2z+2z-(3z+29)=0

We add all the numbers together, and all the variables

4z-(3z+29)=0

We get rid of parentheses

4z-3z-29=0

We add all the numbers together, and all the variables

z-29=0

We move all terms containing z to the left, all other terms to the right

z=29

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