2z+3(z-4)=38

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Solution for 2z+3(z-4)=38 equation: 



2z+3(z-4)=38

We move all terms to the left:

2z+3(z-4)-(38)=0

We multiply parentheses

2z+3z-12-38=0

We add all the numbers together, and all the variables

5z-50=0

We move all terms containing z to the left, all other terms to the right

5z=50

z=50/5

z=10

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