2z+3z*4z=0

Solution for 2z+3z*4z=0 equation:

2z+3z*4z=0

Wy multiply elements

12z^2+2z=0

a = 12; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·12·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*12}=\frac{-4}{24}
=-1/6
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*12}=\frac{0}{24}
=0
$