2z+4(9-3z)=62

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Solution for 2z+4(9-3z)=62 equation: 



2z+4(9-3z)=62

We move all terms to the left:

2z+4(9-3z)-(62)=0

We add all the numbers together, and all the variables

2z+4(-3z+9)-62=0

We multiply parentheses

2z-12z+36-62=0

We add all the numbers together, and all the variables

-10z-26=0

We move all terms containing z to the left, all other terms to the right

-10z=26

z=26/-10

z=-2+3/5

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