2z+4/5*5=z-1*5

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Solution for 2z+4/5*5=z-1*5 equation: 



2z+4/5*5=z-1*5

We move all terms to the left:

2z+4/5*5-(z-1*5)=0

We add all the numbers together, and all the variables

2z-(z-5)+4/5*5=0

We get rid of parentheses

2z-z+5+4/5*5=0

We multiply all the terms by the denominator


2z*5*5-z*5*5+4+5*5*5=0

We add all the numbers together, and all the variables

2z*5*5-z*5*5+129=0

Wy multiply elements

50z*5-25z*5+129=0

Wy multiply elements

250z-125z+129=0

We add all the numbers together, and all the variables

125z+129=0

We move all terms containing z to the left, all other terms to the right

125z=-129

z=-129/125

z=-1+4/125

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