2z+41/2=6

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Solution for 2z+41/2=6 equation: 



2z+41/2=6

We move all terms to the left:

2z+41/2-(6)=0

determiningTheFunctionDomain
2z-6+41/2=0

We multiply all the terms by the denominator


2z*2+41-6*2=0

We add all the numbers together, and all the variables

2z*2+29=0

Wy multiply elements

4z+29=0

We move all terms containing z to the left, all other terms to the right

4z=-29

z=-29/4

z=-7+1/4

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