2z+5/5+8/4=4(2/4+5z)

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Solution for 2z+5/5+8/4=4(2/4+5z) equation: 



2z+5/5+8/4=4(2/4+5z)

We move all terms to the left:

2z+5/5+8/4-(4(2/4+5z))=0



Domain of the equation: 4+5z))!=0

We move all terms containing z to the left, all other terms to the right

5z))!=-4

z!=-4/1

z!=-4

z∈R



We add all the numbers together, and all the variables

2z-(4(+5z+2/4))+5/5+8/4=0

We add all the numbers together, and all the variables

2z-(4(+5z+2/4))+3=0

We multiply all the terms by the denominator


2z*4))-(4(+5z+2+3*4))=0

We add all the numbers together, and all the variables

2z*4))-(4(5z+14))=0

We add all the numbers together, and all the variables

2z*4))-(4(5z=0

Wy multiply elements

8z^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{16}=0$

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