2z+7+2z+13=48

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Solution for 2z+7+2z+13=48 equation: 



2z+7+2z+13=48

We move all terms to the left:

2z+7+2z+13-(48)=0

We add all the numbers together, and all the variables

4z-28=0

We move all terms containing z to the left, all other terms to the right

4z=28

z=28/4

z=7

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