2z-(1+i)z=4+i

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Solution for 2z-(1+i)z=4+i equation:


Simplifying
2z + -1(1 + i) * z = 4 + i

Reorder the terms for easier multiplication:
2z + -1z(1 + i) = 4 + i
2z + (1 * -1z + i * -1z) = 4 + i

Reorder the terms:
2z + (-1iz + -1z) = 4 + i
2z + (-1iz + -1z) = 4 + i

Reorder the terms:
-1iz + 2z + -1z = 4 + i

Combine like terms: 2z + -1z = 1z
-1iz + 1z = 4 + i

Solving
-1iz + 1z = 4 + i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
-1iz + -1i + 1z = 4 + i + -1i

Reorder the terms:
-1i + -1iz + 1z = 4 + i + -1i

Combine like terms: i + -1i = 0
-1i + -1iz + 1z = 4 + 0
-1i + -1iz + 1z = 4

Add '-1z' to each side of the equation.
-1i + -1iz + 1z + -1z = 4 + -1z

Combine like terms: 1z + -1z = 0
-1i + -1iz + 0 = 4 + -1z
-1i + -1iz = 4 + -1z

Reorder the terms:
-4 + -1i + -1iz + z = 4 + -1z + -4 + z

Reorder the terms:
-4 + -1i + -1iz + z = 4 + -4 + -1z + z

Combine like terms: 4 + -4 = 0
-4 + -1i + -1iz + z = 0 + -1z + z
-4 + -1i + -1iz + z = -1z + z

Combine like terms: -1z + z = 0
-4 + -1i + -1iz + z = 0

The solution to this equation could not be determined.

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