2z-(4+i)=8+i

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Solution for 2z-(4+i)=8+i equation:


Simplifying
2z + -1(4 + i) = 8 + i
2z + (4 * -1 + i * -1) = 8 + i
2z + (-4 + -1i) = 8 + i

Reorder the terms:
-4 + -1i + 2z = 8 + i

Solving
-4 + -1i + 2z = 8 + i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
-4 + -1i + -1i + 2z = 8 + i + -1i

Combine like terms: -1i + -1i = -2i
-4 + -2i + 2z = 8 + i + -1i

Combine like terms: i + -1i = 0
-4 + -2i + 2z = 8 + 0
-4 + -2i + 2z = 8

Add '4' to each side of the equation.
-4 + -2i + 4 + 2z = 8 + 4

Reorder the terms:
-4 + 4 + -2i + 2z = 8 + 4

Combine like terms: -4 + 4 = 0
0 + -2i + 2z = 8 + 4
-2i + 2z = 8 + 4

Combine like terms: 8 + 4 = 12
-2i + 2z = 12

Add '-2z' to each side of the equation.
-2i + 2z + -2z = 12 + -2z

Combine like terms: 2z + -2z = 0
-2i + 0 = 12 + -2z
-2i = 12 + -2z

Divide each side by '-2'.
i = -6 + z

Simplifying
i = -6 + z

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