2z-10=2(z-5)

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Solution for 2z-10=2(z-5) equation:


Simplifying
2z + -10 = 2(z + -5)

Reorder the terms:
-10 + 2z = 2(z + -5)

Reorder the terms:
-10 + 2z = 2(-5 + z)
-10 + 2z = (-5 * 2 + z * 2)
-10 + 2z = (-10 + 2z)

Add '10' to each side of the equation.
-10 + 10 + 2z = -10 + 10 + 2z

Combine like terms: -10 + 10 = 0
0 + 2z = -10 + 10 + 2z
2z = -10 + 10 + 2z

Combine like terms: -10 + 10 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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