2z-12=3+11(z+9)

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Solution for 2z-12=3+11(z+9) equation: 



2z-12=3+11(z+9)

We move all terms to the left:

2z-12-(3+11(z+9))=0



We calculate terms in parentheses: -(3+11(z+9)), so:

3+11(z+9)

determiningTheFunctionDomain
11(z+9)+3

We multiply parentheses

11z+99+3

We add all the numbers together, and all the variables

11z+102

Back to the equation:

-(11z+102)



We get rid of parentheses

2z-11z-102-12=0

We add all the numbers together, and all the variables

-9z-114=0

We move all terms containing z to the left, all other terms to the right

-9z=114

z=114/-9

z=-12+2/3

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