2z-3(z+1)=-(5z+9)+z

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Solution for 2z-3(z+1)=-(5z+9)+z equation: 



2z-3(z+1)=-(5z+9)+z

We move all terms to the left:

2z-3(z+1)-(-(5z+9)+z)=0

We multiply parentheses

2z-3z-(-(5z+9)+z)-3=0



We calculate terms in parentheses: -(-(5z+9)+z), so:

-(5z+9)+z

We add all the numbers together, and all the variables

z-(5z+9)

We get rid of parentheses

z-5z-9

We add all the numbers together, and all the variables

-4z-9

Back to the equation:

-(-4z-9)



We add all the numbers together, and all the variables

-1z-(-4z-9)-3=0

We get rid of parentheses

-1z+4z+9-3=0

We add all the numbers together, and all the variables

3z+6=0

We move all terms containing z to the left, all other terms to the right

3z=-6

z=-6/3

z=-2

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