2z-3(z+1)=-(7z+3)+z

Solution for 2z-3(z+1)=-(7z+3)+z equation:

Simplifying
2z + -3(z + 1) = -1(7z + 3) + z

Reorder the terms:
2z + -3(1 + z) = -1(7z + 3) + z
2z + (1 * -3 + z * -3) = -1(7z + 3) + z
2z + (-3 + -3z) = -1(7z + 3) + z

Reorder the terms:
-3 + 2z + -3z = -1(7z + 3) + z

Combine like terms: 2z + -3z = -1z
-3 + -1z = -1(7z + 3) + z

Reorder the terms:
-3 + -1z = -1(3 + 7z) + z
-3 + -1z = (3 * -1 + 7z * -1) + z
-3 + -1z = (-3 + -7z) + z

Combine like terms: -7z + z = -6z
-3 + -1z = -3 + -6z

Add '3' to each side of the equation.
-3 + 3 + -1z = -3 + 3 + -6z

Combine like terms: -3 + 3 = 0
0 + -1z = -3 + 3 + -6z
-1z = -3 + 3 + -6z

Combine like terms: -3 + 3 = 0
-1z = 0 + -6z
-1z = -6z

Solving
-1z = -6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '6z' to each side of the equation.
-1z + 6z = -6z + 6z

Combine like terms: -1z + 6z = 5z
5z = -6z + 6z

Combine like terms: -6z + 6z = 0
5z = 0

Divide each side by '5'.
z = 0

Simplifying
z = 0