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2z-3/5=1/2+2z
We move all terms to the left:
2z-3/5-(1/2+2z)=0
Domain of the equation: 2+2z)!=0We add all the numbers together, and all the variables
We move all terms containing z to the left, all other terms to the right
2z)!=-2
z!=-2/1
z!=-2
z∈R
2z-(+2z+1/2)-3/5=0
We get rid of parentheses
2z-2z-1/2-3/5=0
We calculate fractions
There is no solution for this equation
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