2z-4(z+1)=-(7z+4)+z

Solution for 2z-4(z+1)=-(7z+4)+z equation:

Simplifying
2z + -4(z + 1) = -1(7z + 4) + z

Reorder the terms:
2z + -4(1 + z) = -1(7z + 4) + z
2z + (1 * -4 + z * -4) = -1(7z + 4) + z
2z + (-4 + -4z) = -1(7z + 4) + z

Reorder the terms:
-4 + 2z + -4z = -1(7z + 4) + z

Combine like terms: 2z + -4z = -2z
-4 + -2z = -1(7z + 4) + z

Reorder the terms:
-4 + -2z = -1(4 + 7z) + z
-4 + -2z = (4 * -1 + 7z * -1) + z
-4 + -2z = (-4 + -7z) + z

Combine like terms: -7z + z = -6z
-4 + -2z = -4 + -6z

Add '4' to each side of the equation.
-4 + 4 + -2z = -4 + 4 + -6z

Combine like terms: -4 + 4 = 0
0 + -2z = -4 + 4 + -6z
-2z = -4 + 4 + -6z

Combine like terms: -4 + 4 = 0
-2z = 0 + -6z
-2z = -6z

Solving
-2z = -6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '6z' to each side of the equation.
-2z + 6z = -6z + 6z

Combine like terms: -2z + 6z = 4z
4z = -6z + 6z

Combine like terms: -6z + 6z = 0
4z = 0

Divide each side by '4'.
z = 0

Simplifying
z = 0