2z-5(1z+2)=-8-2z

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Solution for 2z-5(1z+2)=-8-2z equation: 



2z-5(1z+2)=-8-2z

We move all terms to the left:

2z-5(1z+2)-(-8-2z)=0

We add all the numbers together, and all the variables

2z-5(z+2)-(-2z-8)=0

We multiply parentheses

2z-5z-(-2z-8)-10=0

We get rid of parentheses

2z-5z+2z+8-10=0

We add all the numbers together, and all the variables

-1z-2=0

We move all terms containing z to the left, all other terms to the right

-z=2

z=2/-1

z=-2

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