2z-5(4-z)=3(2z-6)+z-2

Solution for 2z-5(4-z)=3(2z-6)+z-2 equation:

Simplifying
2z + -5(4 + -1z) = 3(2z + -6) + z + -2
2z + (4 * -5 + -1z * -5) = 3(2z + -6) + z + -2
2z + (-20 + 5z) = 3(2z + -6) + z + -2

Reorder the terms:
-20 + 2z + 5z = 3(2z + -6) + z + -2

Combine like terms: 2z + 5z = 7z
-20 + 7z = 3(2z + -6) + z + -2

Reorder the terms:
-20 + 7z = 3(-6 + 2z) + z + -2
-20 + 7z = (-6 * 3 + 2z * 3) + z + -2
-20 + 7z = (-18 + 6z) + z + -2

Reorder the terms:
-20 + 7z = -18 + -2 + 6z + z

Combine like terms: -18 + -2 = -20
-20 + 7z = -20 + 6z + z

Combine like terms: 6z + z = 7z
-20 + 7z = -20 + 7z

Add '20' to each side of the equation.
-20 + 20 + 7z = -20 + 20 + 7z

Combine like terms: -20 + 20 = 0
0 + 7z = -20 + 20 + 7z
7z = -20 + 20 + 7z

Combine like terms: -20 + 20 = 0
7z = 0 + 7z
7z = 7z

Add '-7z' to each side of the equation.
7z + -7z = 7z + -7z

Combine like terms: 7z + -7z = 0
0 = 7z + -7z

Combine like terms: 7z + -7z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.