2z-5(z+1)=16

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Solution for 2z-5(z+1)=16 equation: 



2z-5(z+1)=16

We move all terms to the left:

2z-5(z+1)-(16)=0

We multiply parentheses

2z-5z-5-16=0

We add all the numbers together, and all the variables

-3z-21=0

We move all terms containing z to the left, all other terms to the right

-3z=21

z=21/-3

z=-7

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