2z-5(z+12=3+1)

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Solution for 2z-5(z+12=3+1) equation: 



2z-5(z+12=3+1)

We move all terms to the left:

2z-5(z+12-(3+1))=0

We add all the numbers together, and all the variables

2z-5(z+12-4)=0

We multiply parentheses

2z-5z-60+20=0

We add all the numbers together, and all the variables

-3z-40=0

We move all terms containing z to the left, all other terms to the right

-3z=40

z=40/-3

z=-13+1/3

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