2z-5(z+2)=-8

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Solution for 2z-5(z+2)=-8 equation: 



2z-5(z+2)=-8

We move all terms to the left:

2z-5(z+2)-(-8)=0

We add all the numbers together, and all the variables

2z-5(z+2)+8=0

We multiply parentheses

2z-5z-10+8=0

We add all the numbers together, and all the variables

-3z-2=0

We move all terms containing z to the left, all other terms to the right

-3z=2

z=2/-3

z=-2/3

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