2z-5(z+2)=-8-2)

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Solution for 2z-5(z+2)=-8-2) equation: 



2z-5(z+2)=-8-2)

We move all terms to the left:

2z-5(z+2)-(-8-2))=0

We add all the numbers together, and all the variables

2z-5(z+2)-(-10))=0

We add all the numbers together, and all the variables

2z-5(z+2)=0

We multiply parentheses

2z-5z-10=0

We add all the numbers together, and all the variables

-3z-10=0

We move all terms containing z to the left, all other terms to the right

-3z=10

z=10/-3

z=-3+1/3

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