2z-5=-(7z+32)

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Solution for 2z-5=-(7z+32) equation: 



2z-5=-(7z+32)

We move all terms to the left:

2z-5-(-(7z+32))=0



We calculate terms in parentheses: -(-(7z+32)), so:

-(7z+32)

We get rid of parentheses

-7z-32

Back to the equation:

-(-7z-32)



We get rid of parentheses

2z+7z+32-5=0

We add all the numbers together, and all the variables

9z+27=0

We move all terms containing z to the left, all other terms to the right

9z=-27

z=-27/9

z=-3

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