2z-6=(z+2)-10

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Solution for 2z-6=(z+2)-10 equation: 



2z-6=(z+2)-10

We move all terms to the left:

2z-6-((z+2)-10)=0



We calculate terms in parentheses: -((z+2)-10), so:

(z+2)-10

We get rid of parentheses

z+2-10

We add all the numbers together, and all the variables

z-8

Back to the equation:

-(z-8)



We get rid of parentheses

2z-z+8-6=0

We add all the numbers together, and all the variables

z+2=0

We move all terms containing z to the left, all other terms to the right

z=-2

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