2z-6=-2(z+2)-10

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Solution for 2z-6=-2(z+2)-10 equation:



2z-6=-2(z+2)-10
We move all terms to the left:
2z-6-(-2(z+2)-10)=0
We calculate terms in parentheses: -(-2(z+2)-10), so:
-2(z+2)-10
We multiply parentheses
-2z-4-10
We add all the numbers together, and all the variables
-2z-14
Back to the equation:
-(-2z-14)
We get rid of parentheses
2z+2z+14-6=0
We add all the numbers together, and all the variables
4z+8=0
We move all terms containing z to the left, all other terms to the right
4z=-8
z=-8/4
z=-2

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