2z-6=-2(z+2)-10

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Solution for 2z-6=-2(z+2)-10 equation: 



2z-6=-2(z+2)-10

We move all terms to the left:

2z-6-(-2(z+2)-10)=0



We calculate terms in parentheses: -(-2(z+2)-10), so:

-2(z+2)-10

We multiply parentheses

-2z-4-10

We add all the numbers together, and all the variables

-2z-14

Back to the equation:

-(-2z-14)



We get rid of parentheses

2z+2z+14-6=0

We add all the numbers together, and all the variables

4z+8=0

We move all terms containing z to the left, all other terms to the right

4z=-8

z=-8/4

z=-2

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