2z-6=2(z+)-10

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Solution for 2z-6=2(z+)-10 equation: 



2z-6=2(z+)-10

We move all terms to the left:

2z-6-(2(z+)-10)=0

We add all the numbers together, and all the variables

2z-(2(+z)-10)-6=0



We calculate terms in parentheses: -(2(+z)-10), so:

2(+z)-10

We multiply parentheses

2z-10

Back to the equation:

-(2z-10)



We get rid of parentheses

2z-2z+10-6=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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