2z-6=2(z+2)-10

Solution for 2z-6=2(z+2)-10 equation:

Simplifying
2z + -6 = 2(z + 2) + -10

Reorder the terms:
-6 + 2z = 2(z + 2) + -10

Reorder the terms:
-6 + 2z = 2(2 + z) + -10
-6 + 2z = (2 * 2 + z * 2) + -10
-6 + 2z = (4 + 2z) + -10

Reorder the terms:
-6 + 2z = 4 + -10 + 2z

Combine like terms: 4 + -10 = -6
-6 + 2z = -6 + 2z

Add '6' to each side of the equation.
-6 + 6 + 2z = -6 + 6 + 2z

Combine like terms: -6 + 6 = 0
0 + 2z = -6 + 6 + 2z
2z = -6 + 6 + 2z

Combine like terms: -6 + 6 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.