2z-6=2(z+2-10)

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Solution for 2z-6=2(z+2-10) equation: 



2z-6=2(z+2-10)

We move all terms to the left:

2z-6-(2(z+2-10))=0

We add all the numbers together, and all the variables

2z-(2(z-8))-6=0



We calculate terms in parentheses: -(2(z-8)), so:

2(z-8)

We multiply parentheses

2z-16

Back to the equation:

-(2z-16)



We get rid of parentheses

2z-2z+16-6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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