2z-6=4+3(z+1)

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Solution for 2z-6=4+3(z+1) equation:



2z-6=4+3(z+1)
We move all terms to the left:
2z-6-(4+3(z+1))=0
We calculate terms in parentheses: -(4+3(z+1)), so:
4+3(z+1)
determiningTheFunctionDomain 3(z+1)+4
We multiply parentheses
3z+3+4
We add all the numbers together, and all the variables
3z+7
Back to the equation:
-(3z+7)
We get rid of parentheses
2z-3z-7-6=0
We add all the numbers together, and all the variables
-1z-13=0
We move all terms containing z to the left, all other terms to the right
-z=13
z=13/-1
z=-13

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