2z-7(z-9)=28

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Solution for 2z-7(z-9)=28 equation: 



2z-7(z-9)=28

We move all terms to the left:

2z-7(z-9)-(28)=0

We multiply parentheses

2z-7z+63-28=0

We add all the numbers together, and all the variables

-5z+35=0

We move all terms containing z to the left, all other terms to the right

-5z=-35

z=-35/-5

z=+7

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