2z-8=4(z+1)-6

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Solution for 2z-8=4(z+1)-6 equation: 



2z-8=4(z+1)-6

We move all terms to the left:

2z-8-(4(z+1)-6)=0



We calculate terms in parentheses: -(4(z+1)-6), so:

4(z+1)-6

We multiply parentheses

4z+4-6

We add all the numbers together, and all the variables

4z-2

Back to the equation:

-(4z-2)



We get rid of parentheses

2z-4z+2-8=0

We add all the numbers together, and all the variables

-2z-6=0

We move all terms containing z to the left, all other terms to the right

-2z=6

z=6/-2

z=-3

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