2z/(z+3)=3/(z-10)

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Solution for 2z/(z+3)=3/(z-10) equation: 



2z/(z+3)=3/(z-10)

We move all terms to the left:

2z/(z+3)-(3/(z-10))=0



Domain of the equation: (z+3)!=0

We move all terms containing z to the left, all other terms to the right

z!=-3

z∈R





Domain of the equation: (z-10))!=0

z∈R



We calculate fractions


(-18z^2)/((z+3)*(z-10)))+(-(3*(z+3))/((z+3)*(z-10)))=0



We calculate terms in parentheses: -(3*(z+3))/((z+3)*(z-10))), so:

3*(z+3))/((z+3)*(z-10))

We multiply all the terms by the denominator


3*(z+3))

We multiply parentheses

3z+

We add all the numbers together, and all the variables

3z

Back to the equation:

-(3z)



We multiply all the terms by the denominator


(-18z^2)-3z*((z+3)*(z-10)))+(=0

We get rid of parentheses

-18z^2-3z*((z+3)*(z-10)))+(=0

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