2z/(z-4)=(2z-4)/(z-5)

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Solution for 2z/(z-4)=(2z-4)/(z-5) equation: 


D( z )

z-5 = 0

z-4 = 0

z-5 = 0

z-5 = 0

z-5 = 0 // + 5

z = 5

z-4 = 0

z-4 = 0

z-4 = 0 // + 4

z = 4

z in (-oo:4) U (4:5) U (5:+oo)

(2*z)/(z-4) = (2*z-4)/(z-5) // - (2*z-4)/(z-5)

(2*z)/(z-4)-((2*z-4)/(z-5)) = 0

(2*z)/(z-4)+(-1*(2*z-4))/(z-5) = 0

(2*z*(z-5))/((z-4)*(z-5))+(-1*(2*z-4)*(z-4))/((z-4)*(z-5)) = 0

2*z*(z-5)-1*(2*z-4)*(z-4) = 0

2*z-16 = 0

(2*z-16)/((z-4)*(z-5)) = 0

(2*z-16)/((z-4)*(z-5)) = 0 // * (z-4)*(z-5)

2*z-16 = 0

2*z-16 = 0 // + 16

2*z = 16 // : 2

z = 16/2

z = 8

z = 8

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