2z/z+2=3z/2z-2

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Solution for 2z/z+2=3z/2z-2 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(2*z)/z+2 = ((3*z)/2)*z-2 // - ((3*z)/2)*z-2

(2*z)/z-(((3*z)/2)*z)+2+2 = 0

(-3/2)*z^2+(2*z)/z+2+2 = 0

-3/2*z^2 = -6 // : -3/2

z^2 = 4

z^2 = 4 // ^ 1/2

abs(z) = 2

z = 2 or z = -2

z in { 2, -2 }

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