2z/z+4=3z-2z-5

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Solution for 2z/z+4=3z-2z-5 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(2*z)/z+4 = 3*z-(2*z)-5 // - 3*z-(2*z)-5

2*z-(3*z)+(2*z)/z+4+5 = 0

2*z-3*z+(2*z)/z+4+5 = 0

11-z = 0 // - 11

-z = -11 // * -1

z = 11

z = 11

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