2z/z+4=3z/2z-5

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Solution for 2z/z+4=3z/2z-5 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(2*z)/z+4 = ((3*z)/2)*z-5 // - ((3*z)/2)*z-5

(2*z)/z-(((3*z)/2)*z)+4+5 = 0

(-3/2)*z^2+(2*z)/z+4+5 = 0

-3/2*z^2 = -11 // : -3/2

z^2 = 22/3

z^2 = 22/3 // ^ 1/2

abs(z) = (22/3)^(1/2)

z = (22/3)^(1/2) or z = -(22/3)^(1/2)

z in { (22/3)^(1/2), -(22/3)^(1/2) }

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