If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2z^2+z+12=4
We move all terms to the left:
2z^2+z+12-(4)=0
We add all the numbers together, and all the variables
2z^2+z+8=0
a = 2; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·2·8
Δ = -63
Delta is less than zero, so there is no solution for the equation
| -8–2c=5c+13 | | 27-u=8u | | 11v-24-2v+15=-27 | | 21x+3=4x+5 | | -2+7x=2+6 | | 2x(x^2)=0 | | 13x-2=6x+3 | | 7(10^2z)=12 | | 11=x+1.45x | | X=-2.75+1.125y | | 2x+31=6x-9 | | -8+13a+7=-20+14a | | 10^7x=100 | | 100x-250=1000-25x | | -4-3n+4+7=-3n+1-n | | 0.2x=7=27=x | | 0.x=7=27=x | | 4x•12x=320 | | x^2-20x+126=0 | | 2/3x-1/3x=12=x | | 5z-9z+25=29 | | -6(x-13)=-120 | | 65+(11x-7)=180 | | 52=n+16+2n | | 3k-3/2=15 | | -1/7b+2=1=b | | (2x+3)(x)=5000 | | 1/5x-3=-2=x | | -32=-3/5f-17 | | y2-2y=16 | | 5r+15=10=r | | 2x^2-54=2x |